2x^2+17x=370

Solution for 2x^2+17x=370 equation:

2x^2+17x=370

We move all terms to the left:

2x^2+17x-(370)=0

a = 2; b = 17; c = -370;
Δ = b2-4ac
Δ = 172-4·2·(-370)
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3249}=57$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-57}{2*2}=\frac{-74}{4}
=-18+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+57}{2*2}=\frac{40}{4}
=10
$